Electrical Engineering - Series Circuits - Discussion

Ohm's law is V = IR, it says that the voltage is directly proportional to the current. Also, the resistance through the all resistors is zero except third resistor which means that, the voltage will not drop in first two resistors. So, definitely 6V from the power source will be go through the third resistor. According to the ohm's law the voltage drop will be occur in third resistor which will not follow in the fourth and fifth resistors, because they given the resistance of next two resistors as zero.

In series circuit, the current through the each resistor will be same, but not voltage which will vary depends upon the resistance. If resistance is high, voltage drop will be high. We can say the resistance in terms of load. So, the voltage across the third resistor is 6V.

It is 6v.

Question states we have voltage to the circuit and Its equal to 6v. (No dead batteries ect. Sorry)

ALL EXCEPT r3 have zero voltage drop-- the question is stating r3 has a nonzero voltage drop. If all the other resistors have zero drops they have zero resistance-- like ideal wire.

So we only have a single resistor in the circuit r3.

If these resistors were in parallel you wouldn't have a circuit for long because you'd have 4 shorts. The question states a series circuit.

So, the voltage drop across a single resistor in a 6v circuit. Then the answer is 6v. No math required.

Question not having any relevance.

Correct answer for this question is zero.

In a series circuit the voltage drop zero across all resistance except R3 it means this is an open circuit.

Also, it can persume Battery dead. Other circuit shorted should not be a correct argument.
For justifying the given answer you can find out the way.That is all.

Series circuit voltage zero means no current so open circuit or batter dead.

Answer is zero.

According to Question resistors are in series.

And voltage drop in R1, R2, R4 & R5 are zero. Then,

1) Current will also zero in all resistors (V = IR). Because resistor having some resistance according to question.

2) Current in the series is Same so mean Current In R3 will also zero.

3) When current will zero so Vtg will be also Zero (V = IR).

@All.

The question is a little tricky.

1) If we consider it as a series circuit with very very little current (very high resistance except for R3) say in micro amps then only it's possible to get nearly 6v across R3 (not exactly 6v).

2) In case if the resistors except R3 got damaged (shorted) then only 6v across R3.

In series connected resistors, the flowing current supposed to be equal. If you are measuring across any of the resistors, and the meter reads 0v, it means answer A is right. If you are measuring with the respect to common terminal, 6v reading means that R2 resistor is broken. Explanation is not correct.

If the voltage across any resistor is zero that means resistor is shorted and the whole voltage appears across the resistor active in the circuit.

As in the question it is give that R3 is active so the whole voltage appears across it. The voltage give in question is 6v.

Therefore answer: 6V.

@Aman.

You should think that we are talking about zero voltage but not for zero cureent. It means all the resistors except R3 contains zero resistance. So all voltage drop is across register R3 which is the total voltage drop due to current flowing through it opposed by its resistance.

If in the string all resistors are connected in series, than if voltage across R1, R2 is zero then why there can be a voltage on R3. If there is no voltage then there must not be any current flowing.

Please answer me if you have an appropriate one.

If current through each resistor except R3 is zero. It means that they are open circuit. They have no mean in the circuit. So when current through R1 is zero it will not flow to next resistor. Hence all the resistors will have zero current.