Electrical Engineering - Series Circuits - Discussion

We know in series,

V=V1+V2+V3+V4+V5
=>6=0+0+V3+0+0
=>V3=6v.

@All.

The question is a little tricky.

1) If we consider it as a series circuit with very very little current (very high resistance except for R3) say in micro amps then only it's possible to get nearly 6v across R3 (not exactly 6v).

2) In case if the resistors except R3 got damaged (shorted) then only 6v across R3.

The series circuit current is same voltage is divided according to statement all resistor voltage drop is zero then voltage appears r3 resistor so r3=6v.

V = IR.
R = V/I,
V = I*V/I.
V = V=6V.

It is the correct answer.

It is 6v.

Question states we have voltage to the circuit and Its equal to 6v. (No dead batteries ect. Sorry)

ALL EXCEPT r3 have zero voltage drop-- the question is stating r3 has a nonzero voltage drop. If all the other resistors have zero drops they have zero resistance-- like ideal wire.

So we only have a single resistor in the circuit r3.

If these resistors were in parallel you wouldn't have a circuit for long because you'd have 4 shorts. The question states a series circuit.

So, the voltage drop across a single resistor in a 6v circuit. Then the answer is 6v. No math required.

If all resistors (except R3 are) considered having zero ohm resistance, then this condition satisfies.

R3 is an open circuit, so all other resistor voltage is 0, r3 will show 6 voltage.

R3 is load.

Voltage is zero means register is shorted i.e. zero valued resistor is present there and therefore the entire value of circuit voltage appears across the resistor having some value. So the right answer will be 6v.

Ohm's law is V = IR, it says that the voltage is directly proportional to the current. Also, the resistance through the all resistors is zero except third resistor which means that, the voltage will not drop in first two resistors. So, definitely 6V from the power source will be go through the third resistor. According to the ohm's law the voltage drop will be occur in third resistor which will not follow in the fourth and fifth resistors, because they given the resistance of next two resistors as zero.

In series circuit, the current through the each resistor will be same, but not voltage which will vary depends upon the resistance. If resistance is high, voltage drop will be high. We can say the resistance in terms of load. So, the voltage across the third resistor is 6V.