Electrical Engineering - Series Circuits - Discussion

Discussion Forum : Series Circuits - General Questions (Q.No. 2)
2.
A string of five series resistors is connected across a 6 V battery. Zero voltage is measured across all resistors except R3. The voltage across R3 is
0 V
1.2 V
6 V
0.6 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
51 comments Page 4 of 6.

SANKAR said:   1 decade ago
Resistor connected in series. Circuit current is 0.5A BUT R1245 VOLT IS 0V. So according to ohm's law V = I*R = 6V.

Rutesh said:   1 decade ago
Simple,

v1+v2+v3+v4+v5 = V,

ir1 + ir2 + v3 +ir4 +ir5 = 6,(V=6),

As per @Satosh formula,

We get v3 = V = 6v.

Lakmal said:   1 decade ago
Like R1245 resistors are 0 ohms. Like a wire. Like 6v battery dirrect connect to R3 resistor. So answer is 6v.

Judhistir said:   1 decade ago
Here voltage drop across r1 r2 r4 and r5 is zero. That means r1+r2+r4+r5=0. So voltage across r3 resistor=6v.

Sher Ali said:   1 decade ago
I think the Current is same in series circuit. So if all the resistors are 0 ohm then the R3 will be 0 Ohm.

Aman said:   1 decade ago
In series connection current is always same so value of current across r3 is also zero hence no voltage.

Shubham Patil said:   8 years ago
If all resistors (except R3 are) considered having zero ohm resistance, then this condition satisfies.
(2)

Santhosh said:   1 decade ago
6volts given to resistor(r1(0)+r2(0)+r3+r4(0)+r5(0))= we obtain the same six volts at the end.

Ahmed said:   1 decade ago
Correct answer is A for series case.

It would be correct if the connection is parallel.

Gijo said:   8 years ago
R3 is an open circuit, so all other resistor voltage is 0, r3 will show 6 voltage.
(1)


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