Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 24)
24.
The total resistance of a circuit is 680
. The percentage of the total voltage appearing across a 47
resistor that makes up part of the total series resistance is


Discussion:
13 comments Page 1 of 2.
Allulavu said:
3 months ago
Thanks all for explaining the answer.
TUSHAR NAKUM said:
3 years ago
At 680 ohm Resistance = Voltage is 100%,
Then at 47-ohm resistance = Voltage is?
47 *100/680 = 6.9117647045 ~ 6.91%.
Then at 47-ohm resistance = Voltage is?
47 *100/680 = 6.9117647045 ~ 6.91%.
(1)
Karthik Netha said:
4 years ago
@Boss.
Nice explanation Thanks.
Nice explanation Thanks.
Sandy said:
9 years ago
Awesome explanation @Sandeep.
Jagadesh said:
9 years ago
The percentage of voltage across any resistor = (Resistor value/Total resistance)*100.
Percentage v = (47/680)*100.
= 6.9%.
Percentage v = (47/680)*100.
= 6.9%.
(1)
Sandeep patil said:
10 years ago
Above all answers are correct.
Let me answer in different way. Since total resistance is 680 ohms. One of them is 47 ohm.
So 680-47 = 633 ohms right, means will imagine one resistor is having 633 ohms and another is 47 ohms ok.
And in above options which option is having least % that will be the % voltage across 47 ohm resistor. i.e. 6.9%.
Let me answer in different way. Since total resistance is 680 ohms. One of them is 47 ohm.
So 680-47 = 633 ohms right, means will imagine one resistor is having 633 ohms and another is 47 ohms ok.
And in above options which option is having least % that will be the % voltage across 47 ohm resistor. i.e. 6.9%.
Mahesh said:
1 decade ago
Since it is asked in percentage lets take V as 100%.
Total series resistance is 680 ohms.
For 680 it takes 100% of V.
680 ohms =100%.
47 ohms = ?
Cross multiply you will get 6.91%.
Total series resistance is 680 ohms.
For 680 it takes 100% of V.
680 ohms =100%.
47 ohms = ?
Cross multiply you will get 6.91%.
Drethi said:
1 decade ago
I didn't get. Please explain me.
Sairam said:
1 decade ago
Since voltage and resistance are having linear relationship so % of voltage drop across 47 Ohm resistance can be calculated as 47/680 = 6.91%.
VIDYA SAGAR said:
1 decade ago
680....>100%.
47....>?
680*X = 47*100.
X = 4700/680.
X = 6.91%.
47....>?
680*X = 47*100.
X = 4700/680.
X = 6.91%.
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