Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 24)
24.
The total resistance of a circuit is 680 
. The percentage of the total voltage appearing across a 47 resistor that makes up part of the total series resistance is
. The percentage of the total voltage appearing across a 47 resistor that makes up part of the total series resistance isDiscussion:
13 comments Page 2 of 2.
The BOSS said:
1 decade ago
100%v at 680ohm
-(x)-%v at 47ohm
find x (cross multiplication)
x = 100.47 / 680 = 6.91%
-(x)-%v at 47ohm
find x (cross multiplication)
x = 100.47 / 680 = 6.91%
Ali Alrushoud said:
1 decade ago
I constant in series circuit
V=IR = I 680
V'=Ir = I 47
V'/V = I 47 / I 680 = 47 / 680 = 0.0691
V' = 6.91% V
V=IR = I 680
V'=Ir = I 47
V'/V = I 47 / I 680 = 47 / 680 = 0.0691
V' = 6.91% V
DILEEP M JOHN said:
1 decade ago
V=IR
series----I constant
v prop. R
v prop 680
v' prop 47
dividing v'=47/680V
v'=.069V
ie 6.9 %
series----I constant
v prop. R
v prop 680
v' prop 47
dividing v'=47/680V
v'=.069V
ie 6.9 %
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