Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 10)
10.
All the voltage drops and the source voltage added together in a series circuit is equal to
Discussion:
23 comments Page 2 of 3.
Jagadesh said:
10 years ago
According to Kirchoff's voltage law the algebraic sum of voltage sources and drops in a closed circuit must be equal to zero.
S.kirthika said:
1 decade ago
v=v1+v2.
v-v1-v2=0.
v-v1-v2=0.
Bidisha said:
1 decade ago
This happens because of KVL.
Aruldoss said:
1 decade ago
Very good @Richmond, the word algebraic sum should be added for this answer unless it is wrong answer @Vishal.
Vishal said:
1 decade ago
VS : Source voltage.
VD : Voltage drops.
VS = -VD.
So VS+VD = 0.
VD : Voltage drops.
VS = -VD.
So VS+VD = 0.
Richmond botchwey said:
1 decade ago
The question ought to be technical enough to prevent different answers. To me adding all the voltage drops and the source voltage gives twice the source voltage unless the word 'algebraic sum' is used. Engineers pay much attention to detail.
SIVA said:
1 decade ago
VS : Source voltage.
VD : Voltage drops.
VS = -VD.
So VS+VD = 0.
VD : Voltage drops.
VS = -VD.
So VS+VD = 0.
Naveen said:
1 decade ago
@pearl: KVL is Vs1+Vs2+....=VD
IF VD is negative then VS=-VD gives VS+VD cannot be equal to Zero
Thats Wrong..KVL says that Sum of INCOMING voltages is Equal to Outgoing
IF VD is negative then VS=-VD gives VS+VD cannot be equal to Zero
Thats Wrong..KVL says that Sum of INCOMING voltages is Equal to Outgoing
Pearl said:
1 decade ago
Voltage source have posiive polarities and drops will be considered negative so appling kvl sum will be 0.
Srinivasan M said:
1 decade ago
In series circuit applied voltage equal to algebraic sum of individual voltage drop in each resistors which are connected ina circuit.
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