Electrical Engineering - Series Circuits - Discussion

If we have given some value of voltage in a series ckt so exactly voltage drop due to series ckt that's why the sum of all the voltage drops equals to the source voltage.

Vs = Vd, or Vs - Vd = 0.

For example; we have given 5V as the source voltage and we have two resistors one drop 2V and the other drop 3V, then first we add drop voltage, which is equal to Vd= 2V+3V= 5V.

Now simply we know that Vs = Vd therefore,
5V = 5V or 5V-5V=0, 0volts.

The question ought to be technical enough to prevent different answers. To me adding all the voltage drops and the source voltage gives twice the source voltage unless the word 'algebraic sum' is used. Engineers pay much attention to detail.

@pearl: KVL is Vs1+Vs2+....=VD

IF VD is negative then VS=-VD gives VS+VD cannot be equal to Zero

Thats Wrong..KVL says that Sum of INCOMING voltages is Equal to Outgoing

In series circuit applied voltage equal to algebraic sum of individual voltage drop in each resistors which are connected ina circuit.

It is depending on kvl.

According to kvl, the algebraic sum of voltage sources and drops in a closed circuit must be equal to zero.

According to Kirchoff's voltage law the algebraic sum of voltage sources and drops in a closed circuit must be equal to zero.

If we consider above statment as kvl, here niether mention about the direction nor algebric sum of the voltages.

Very good @Richmond, the word algebraic sum should be added for this answer unless it is wrong answer @Vishal.

Supply voltage is positive whereas voltage drop are taken negative. Thus the summation of all becomes zero.

Voltage source have posiive polarities and drops will be considered negative so appling kvl sum will be 0.