Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 10)
10.
All the voltage drops and the source voltage added together in a series circuit is equal to
Discussion:
23 comments Page 1 of 3.
Usman Nazir said:
4 years ago
VS : Source voltage.
VD : Voltage drops.
VS = -VD.
So, VS + VD = 0.
VD : Voltage drops.
VS = -VD.
So, VS + VD = 0.
(3)
VINAYASHRI.C. M. said:
5 years ago
It is depending on kvl.
According to kvl, the algebraic sum of voltage sources and drops in a closed circuit must be equal to zero.
According to kvl, the algebraic sum of voltage sources and drops in a closed circuit must be equal to zero.
(1)
Sumit kashyap said:
9 years ago
Only apply KVL both algebraic sum is 0.
(1)
S.kirthika said:
1 decade ago
v=v1+v2.
v-v1-v2=0.
v-v1-v2=0.
Lawrence said:
3 years ago
The answer is zero according to KVL.
Engr Murtaza Manzoor Tunio said:
5 years ago
If we have given some value of voltage in a series ckt so exactly voltage drop due to series ckt that's why the sum of all the voltage drops equals to the source voltage.
Vs = Vd, or Vs - Vd = 0.
For example; we have given 5V as the source voltage and we have two resistors one drop 2V and the other drop 3V, then first we add drop voltage, which is equal to Vd= 2V+3V= 5V.
Now simply we know that Vs = Vd therefore,
5V = 5V or 5V-5V=0, 0volts.
Vs = Vd, or Vs - Vd = 0.
For example; we have given 5V as the source voltage and we have two resistors one drop 2V and the other drop 3V, then first we add drop voltage, which is equal to Vd= 2V+3V= 5V.
Now simply we know that Vs = Vd therefore,
5V = 5V or 5V-5V=0, 0volts.
Satyajit said:
7 years ago
Twice is correct.
Basava ns said:
7 years ago
It always depends on kvl.
Bibek said:
7 years ago
Supply voltage is positive whereas voltage drop are taken negative. Thus the summation of all becomes zero.
Ananya said:
9 years ago
Very good answers.
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