# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 5)

5.

A 12 resistor, a 40 F capacitor, and an 8 mH coil are in series across an ac source. The resonant frequency is

Discussion:

10 comments Page 1 of 1.
Srinu said:
1 decade ago

f=1/{2(pi)*sqrt(L*C)}

NIBHAS said:
1 decade ago

What is pi formula?

Rohit jayara said:
1 decade ago

What is pi formula? please tell me.

Akshaya said:
1 decade ago

pi has a constant value = 3.14.

Sandy said:
10 years ago

f = (1/2*pie*sqrt(LC)).

Arun dahiwal said:
10 years ago

RLC circuit and resonance.

Anand said:
9 years ago

At resonance Xc = XL.

i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.

F = 1/(2*3.14*sqrt(L*C)).

By substituting values we get F = 281 Hz.

i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.

F = 1/(2*3.14*sqrt(L*C)).

By substituting values we get F = 281 Hz.

Jomel said:
8 years ago

What is the exact formula f = (1/2 * pi * sqrt(LC)) or f = 1/(2 * pi * sqrt(LC)?

Faiza Malik said:
6 years ago

Exact formula is calculated as;

XL=XC.

2*π*f*L=1/(2*π*f*C).

for frequency we can simply it as;

2*π* f^2 *L=1/2*π*C.

f=1/2*π*√(L*C).

XL=XC.

2*π*f*L=1/(2*π*f*C).

for frequency we can simply it as;

2*π* f^2 *L=1/2*π*C.

f=1/2*π*√(L*C).

Harshu Randhawa said:
3 years ago

Not getting it, Please anyone explain clearly.

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