Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 5)
5.
A 12 resistor, a 40 F capacitor, and an 8 mH coil are in series across an ac source. The resonant frequency is
28.1 Hz
281 Hz
2,810 Hz
10 kHz
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
10 comments Page 1 of 1.

Harshu Randhawa said:   2 years ago
Not getting it, Please anyone explain clearly.

Faiza Malik said:   4 years ago
Exact formula is calculated as;
XL=XC.

2*π*f*L=1/(2*π*f*C).

for frequency we can simply it as;

2*π* f^2 *L=1/2*π*C.
f=1/2*π*√(L*C).

Jomel said:   7 years ago
What is the exact formula f = (1/2 * pi * sqrt(LC)) or f = 1/(2 * pi * sqrt(LC)?

Anand said:   8 years ago
At resonance Xc = XL.

i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.

F = 1/(2*3.14*sqrt(L*C)).

By substituting values we get F = 281 Hz.

Arun dahiwal said:   8 years ago
RLC circuit and resonance.

Sandy said:   8 years ago
f = (1/2*pie*sqrt(LC)).

Akshaya said:   9 years ago
pi has a constant value = 3.14.

Rohit jayara said:   9 years ago
What is pi formula? please tell me.

NIBHAS said:   9 years ago
What is pi formula?

Srinu said:   1 decade ago
f=1/{2(pi)*sqrt(L*C)}

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