Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion :: RLC Circuits and Resonance - General Questions (Q.No.5)

5. 

A 12 resistor, a 40 F capacitor, and an 8 mH coil are in series across an ac source. The resonant frequency is

[A]. 28.1 Hz
[B]. 281 Hz
[C]. 2,810 Hz
[D]. 10 kHz

Answer: Option B

Explanation:

No answer description available for this question.

Srinu said: (Jan 26, 2011)  
f=1/{2(pi)*sqrt(L*C)}

Nibhas said: (Aug 31, 2013)  
What is pi formula?

Rohit Jayara said: (Dec 19, 2013)  
What is pi formula? please tell me.

Akshaya said: (Mar 1, 2014)  
pi has a constant value = 3.14.

Sandy said: (Aug 31, 2014)  
f = (1/2*pie*sqrt(LC)).

Arun Dahiwal said: (Jan 7, 2015)  
RLC circuit and resonance.

Anand said: (Jul 21, 2015)  
At resonance Xc = XL.

i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.

F = 1/(2*3.14*sqrt(L*C)).

By substituting values we get F = 281 Hz.

Jomel said: (Jul 22, 2016)  
What is the exact formula f = (1/2 * pi * sqrt(LC)) or f = 1/(2 * pi * sqrt(LC)?

Faiza Malik said: (Dec 8, 2018)  
Exact formula is calculated as;
XL=XC.

2*π*f*L=1/(2*π*f*C).

for frequency we can simply it as;

2*π* f^2 *L=1/2*π*C.
f=1/2*π*√(L*C).

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