Electrical Engineering - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 5)
5.
A 12 resistor, a 40 F capacitor, and an 8 mH coil are in series across an ac source. The resonant frequency is
Discussion:
10 comments Page 1 of 1.
Harshu Randhawa said:
3 years ago
Not getting it, Please anyone explain clearly.
Faiza Malik said:
6 years ago
Exact formula is calculated as;
XL=XC.
2*π*f*L=1/(2*π*f*C).
for frequency we can simply it as;
2*π* f^2 *L=1/2*π*C.
f=1/2*π*√(L*C).
XL=XC.
2*π*f*L=1/(2*π*f*C).
for frequency we can simply it as;
2*π* f^2 *L=1/2*π*C.
f=1/2*π*√(L*C).
Jomel said:
8 years ago
What is the exact formula f = (1/2 * pi * sqrt(LC)) or f = 1/(2 * pi * sqrt(LC)?
Anand said:
9 years ago
At resonance Xc = XL.
i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.
F = 1/(2*3.14*sqrt(L*C)).
By substituting values we get F = 281 Hz.
i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.
F = 1/(2*3.14*sqrt(L*C)).
By substituting values we get F = 281 Hz.
Arun dahiwal said:
10 years ago
RLC circuit and resonance.
Sandy said:
1 decade ago
f = (1/2*pie*sqrt(LC)).
Akshaya said:
1 decade ago
pi has a constant value = 3.14.
Rohit jayara said:
1 decade ago
What is pi formula? please tell me.
NIBHAS said:
1 decade ago
What is pi formula?
Srinu said:
1 decade ago
f=1/{2(pi)*sqrt(L*C)}
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