Discussion :: RLC Circuits and Resonance - General Questions (Q.No.5)
A 12 resistor, a 40 F capacitor, and an 8 mH coil are in series across an ac source. The resonant frequency is
Answer: Option B
No answer description available for this question.
|Srinu said: (Jan 26, 2011)|
|Nibhas said: (Aug 31, 2013)|
|What is pi formula?|
|Rohit Jayara said: (Dec 19, 2013)|
|What is pi formula? please tell me.|
|Akshaya said: (Mar 1, 2014)|
|pi has a constant value = 3.14.|
|Sandy said: (Aug 31, 2014)|
|f = (1/2*pie*sqrt(LC)).|
|Arun Dahiwal said: (Jan 7, 2015)|
|RLC circuit and resonance.|
|Anand said: (Jul 21, 2015)|
|At resonance Xc = XL.
i.e 4 1/(2*3.14*C*F) = 2*3.14*L*F.
F = 1/(2*3.14*sqrt(L*C)).
By substituting values we get F = 281 Hz.
|Jomel said: (Jul 22, 2016)|
|What is the exact formula f = (1/2 * pi * sqrt(LC)) or f = 1/(2 * pi * sqrt(LC)?|
|Faiza Malik said: (Dec 8, 2018)|
|Exact formula is calculated as;
for frequency we can simply it as;
2*π* f^2 *L=1/2*π*C.
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