# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 2)
2.
In a series RLC circuit that is operating above the resonant frequency, the current
lags the applied voltage
is in phase with the applied voltage
is zero
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

according to the graph of resonance, above resonant frequency, inductive reactance is more than capacitive reactance, so net is inductive and thus the current lags applied voltage

Balamurugan C said:   1 decade ago
AT RESONANT CONDITION

XL=XC @ RESONANT FREQUENCY

RESONANT FREQUENCY MORE IF XL>XC AND LESS IF XL<XC

HERE IT IS MORE AND IT MEANS XL IS HIGH AND HENCE L IS HIGH (XL=360FL)

L ALWAYS TAKES LAGS THE CURRENT

HENCE THE CURRENT LAGS THE APPLIED VOLTAGE

Abhi said:   10 years ago
At frequencies above the resonance frequency the series RLC circuit. Behaves as an inductive load (evident from equivalent impedance equation) hence current will lag.

Manindra said:   10 years ago
At resonant frequency, (Xl=Xc).

Above resonant frequency, (Xl>Xc).

Below resonant frequency (Xl<Xc).

Aggrey kere said:   10 years ago
At resonance, Xl =XC. Thus there no phase angle. Therefore; no lug or lead.

RAJ said:   9 years ago
At resonance I in phase with V.

Varshney said:   9 years ago
Above resonance frequency current lags voltage because at this situation XL>XC.

Sandeep wasnik said:   9 years ago
At resonant condition.

XL = XC @ resonant frequency.

Resonant frequency more if XL>XC and less if XL<XC.

Here it is more and it means XL is high and hence L is high (XL = 360FL).

L always takes lags the current.

Hence the current lags the applied voltage.

Sandeep sana said:   9 years ago
Resonant frequency XL>XC. So current lags the applied voltage.

Pruthviraj said:   7 years ago
Resonant frequency(fr) = 1/(2 * 3.14 * (LC)1/2,
Take that root.
Given that RLC circuit is above the fr then we know XL > XC in case fr is more then current must be low and that case current should be lags by applied voltage.