# Electrical Engineering - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 6)

6.

The impedance at the resonant frequency of a series

*RLC*circuit with*L*= 20 mH,*C*= 0.02 F, and*R*= 90 is_{W}Discussion:

8 comments Page 1 of 1.
Chithra said:
1 decade ago

At resonant frequency, Z=R (since L=C)

Prasanthi said:
1 decade ago

Minimum impedance at resonannce frequency z= sqrt(r8r + (xl -xc )power2 = r

wl = wl;xc = 1/wc;w =1/ sqrt(lc);

wl = wl;xc = 1/wc;w =1/ sqrt(lc);

(1)

Arun said:
9 years ago

In series circuit at resonance Z=R. Hence Z=R=90 ohm.

(1)

Sk mybelli said:
9 years ago

At resonance Xl = Xc, Z = R enough.

Abhay said:
9 years ago

At resonance xl = xc and that's why xl-xc = 0, so z = R.

Sweety said:
6 years ago

At resonance Xl = Xc, Z = R.

Kikani dixita said:
5 years ago

RLC series in Resonant frequency :Z = R.

In Resonant position *(L=C).

In Resonant position *(L=C).

Sakib Ahmed said:
2 years ago

At resonance, the impedance of the circuit is equal to the resistance value as Z = R.

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