Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 1)
1.
A 1.5 k
resistor and a coil with a 2.2 k inductive reactance are in series across an 18 V ac source. The power factor is
resistor and a coil with a 2.2 k inductive reactance are in series across an 18 V ac source. The power factor isDiscussion:
19 comments Page 1 of 2.
Kalyan G said:
3 years ago
Z=(r^2+XL^2)^1/2=2663.
P.f = cosq = r/z
0.564.
P.f = cosq = r/z
0.564.
Siddharth said:
4 years ago
Power factor = R ÷ Z.
So, R = 1.3k ohm = 1.3 * 10^3 =1300 ohm,
inductive reactians FL = 2.2k ohm =2.2 * 10^3,
= 2200 ohm.
&. Z = (?).
Z = √(R^2 + FL^2),
Z = √(1500^2 + 2200^2),
Z= 2663.
& Power factor = R ÷ Z,
= 1500 ÷ 2663,
= 0.5632.
So, ans is (0.564).
So, R = 1.3k ohm = 1.3 * 10^3 =1300 ohm,
inductive reactians FL = 2.2k ohm =2.2 * 10^3,
= 2200 ohm.
&. Z = (?).
Z = √(R^2 + FL^2),
Z = √(1500^2 + 2200^2),
Z= 2663.
& Power factor = R ÷ Z,
= 1500 ÷ 2663,
= 0.5632.
So, ans is (0.564).
(2)
Arpana singh said:
5 years ago
R/Z=0.405 not 0.564.
Manoj Khodade said:
6 years ago
How to solve? please details.
Saipriya said:
7 years ago
Describe or view the process of the answer.
Vicky said:
7 years ago
cos(q) can never be greater than 1.
G1KUMAR said:
7 years ago
z = (r^2 + x^2)^(1/2).
Ccos = r/z.
Ccos = r/z.
Pavan said:
8 years ago
Power factor indicates efficiency of the circuit.
VENKATESH said:
8 years ago
R = 1.5.
Xl = 2.2.
Z = Root of R square+xl square.
Cos = R/Z.
Xl = 2.2.
Z = Root of R square+xl square.
Cos = R/Z.
(1)
Shenoy said:
8 years ago
Power factor always less than 1 use common sense, so simple.
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