Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 1)
1.
A 1.5 k resistor and a coil with a 2.2 k inductive reactance are in series across an 18 V ac source. The power factor is
564
0.564
6.76
55.7
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
20 comments Page 2 of 2.

Shenoy said:   1 decade ago
Power factor always less than 1 use common sense, so simple.
(1)

Hadiro tafoua said:   1 decade ago
Using all method above we get close intervals of answers. Since it all corresponds to electric quantities.

Noel Zamora said:   1 decade ago
tan 2.2/1.5 = 1.4667, arc tan 1.4667 = 55.71 deg.,

Therefore cos 55.71 deg. = 0.564 or pf = 0.564(lagging).

Shaila kedar said:   1 decade ago
Power factor is always less than 1.

AMIT KUMAR JAISWAL said:   1 decade ago
POWER FACTOR = (R/Z).

Z = SQRT(1.5^2 +2.2^2).

Z = 2.662.

P.F. = 1.5/2.662 = .563.

Ryan said:   1 decade ago
Z = sqrt(1500^2+2200^2) = 2663.

pf = R/Z = 1500/2663 = 0.564.

Yousuf said:   1 decade ago
|z|=sqrt(1500^2+2200^2)=2663
Angle=inverse tan(2200\1500)=55.7
Power Factor=Cos(55.7)=0.564

Karimulla said:   1 decade ago
Generally power factor i.e. cos(angle b/w v,i) always less than one.

Manfrizy said:   1 decade ago
R/Z = 0.405 not 0.564 as you put it Sanjeeb

SANJEEB said:   1 decade ago
COSQ=R/Z=1.5/1.5+2.2=0.564


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