# Electrical Engineering - RL Circuits - Discussion

### Discussion :: RL Circuits - General Questions (Q.No.13)

13.

In a parallel RL circuit, there are 3 A rms in the resistive branch and 3 A rms in the inductive branch. The total rms current is

 [A]. 6 A [B]. 424 mA [C]. 4.24 A [D]. 42.4 A

Explanation:

No answer description available for this question.

 Mohaan said: (Jun 1, 2011) sq root of(3sq=3sq)=4.24

 Swati said: (Oct 1, 2011) Can anyone explain this?

 Vaibhav said: (Oct 23, 2011) Sq root of (3^2+3^2) = 3*1.414 = 4.24

 Sky Net said: (Nov 15, 2014) Can anyone tell me base of this rule?

 Vall said: (Dec 1, 2014) According phasor diagram of current of parallel R-L circuit.

 Savita said: (May 22, 2015) Answer A is right. Irmstotal = IRrms+ILrms. Itotal = 3+3 = 6 A.

 Tejeas said: (May 25, 2015) @Savita is right 6A. Answer is in RMS value only no need to multiply 6A by 1.414.

 Sanju said: (Jun 3, 2015) In parallel circuit current are additive. It = I1+I2. It = 3+3. It = 6. Itrms = 6*0.707. Itrms = 4.242.

 Shobhit said: (Aug 29, 2015) 6A since the type of load won't matter for parallel current distribution.

 Hassan said: (Sep 27, 2015) He ask about I total in rms on in I max. The answer is A.

 Hemant said: (Nov 18, 2016) (3)2 + (3)2 = 18, √18 = 4.2.

 Harsha said: (Nov 26, 2017) Since the given current values are in RMS and the total current to be found in RMS then the total current will be 6 A. Why are you doing it for max value?

 Hanumantha said: (Jun 26, 2019) Irms = √(√(i1rms)+ √(i2rms)) Because i1rms=i2rms=3amps. Irms = √(2√(irms)), Irms = √(2)*irms, Irms = 1.414*3 = 4.2a.