Electrical Engineering - RL Circuits - Discussion

Discussion :: RL Circuits - General Questions (Q.No.13)

13. 

In a parallel RL circuit, there are 3 A rms in the resistive branch and 3 A rms in the inductive branch. The total rms current is

[A]. 6 A
[B]. 424 mA
[C]. 4.24 A
[D]. 42.4 A

Answer: Option C

Explanation:

No answer description available for this question.

Mohaan said: (Jun 1, 2011)  
sq root of(3sq=3sq)=4.24

Swati said: (Oct 1, 2011)  
Can anyone explain this?

Vaibhav said: (Oct 23, 2011)  
Sq root of (3^2+3^2) = 3*1.414 = 4.24

Sky Net said: (Nov 15, 2014)  
Can anyone tell me base of this rule?

Vall said: (Dec 1, 2014)  
According phasor diagram of current of parallel R-L circuit.

Savita said: (May 22, 2015)  
Answer A is right.

Irmstotal = IRrms+ILrms.
Itotal = 3+3 = 6 A.

Tejeas said: (May 25, 2015)  
@Savita is right 6A. Answer is in RMS value only no need to multiply 6A by 1.414.

Sunil said: (May 28, 2015)  
Please confirm the answer anyone.

Sanju said: (Jun 3, 2015)  
In parallel circuit current are additive.

It = I1+I2.
It = 3+3.
It = 6.

Itrms = 6*0.707.
Itrms = 4.242.

Shobhit said: (Aug 29, 2015)  
6A since the type of load won't matter for parallel current distribution.

Hassan said: (Sep 27, 2015)  
He ask about I total in rms on in I max.

The answer is A.

Hemant said: (Nov 18, 2016)  
(3)2 + (3)2 = 18, √18 = 4.2.

Harsha said: (Nov 26, 2017)  
Since the given current values are in RMS and the total current to be found in RMS then the total current will be 6 A.

Why are you doing it for max value?

Hanumantha said: (Jun 26, 2019)  
Irms = √(√(i1rms)+ √(i2rms)) Because i1rms=i2rms=3amps.
Irms = √(2√(irms)),
Irms = √(2)*irms,
Irms = 1.414*3 = 4.2a.

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