Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 13)
13.
In a parallel RL circuit, there are 3 A rms in the resistive branch and 3 A rms in the inductive branch. The total rms current is
Discussion:
15 comments Page 1 of 2.
Muppuri Srinivasulu said:
3 years ago
Can anyone explain this in detail?
Hanumantha said:
6 years ago
Irms = √(√(i1rms)+ √(i2rms)) Because i1rms=i2rms=3amps.
Irms = √(2√(irms)),
Irms = √(2)*irms,
Irms = 1.414*3 = 4.2a.
Irms = √(2√(irms)),
Irms = √(2)*irms,
Irms = 1.414*3 = 4.2a.
Harsha said:
8 years ago
Since the given current values are in RMS and the total current to be found in RMS then the total current will be 6 A.
Why are you doing it for max value?
Why are you doing it for max value?
Hemant said:
9 years ago
(3)2 + (3)2 = 18, √18 = 4.2.
HASSAN said:
10 years ago
He ask about I total in rms on in I max.
The answer is A.
The answer is A.
Shobhit said:
1 decade ago
6A since the type of load won't matter for parallel current distribution.
Sanju said:
1 decade ago
In parallel circuit current are additive.
It = I1+I2.
It = 3+3.
It = 6.
Itrms = 6*0.707.
Itrms = 4.242.
It = I1+I2.
It = 3+3.
It = 6.
Itrms = 6*0.707.
Itrms = 4.242.
(1)
Sunil said:
1 decade ago
Please confirm the answer anyone.
Tejeas said:
1 decade ago
@Savita is right 6A. Answer is in RMS value only no need to multiply 6A by 1.414.
Savita said:
1 decade ago
Answer A is right.
Irmstotal = IRrms+ILrms.
Itotal = 3+3 = 6 A.
Irmstotal = IRrms+ILrms.
Itotal = 3+3 = 6 A.
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