Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 4)
                   
                                       
                                4.
To increase the current in a series RL circuit, the frequency
 
                                    Discussion:
7 comments Page 1 of 1.
                
                        Anonymous said: 
                         
                        1 decade ago
                
                In series RL circuit voltage increases as frequency decreases but voltage is directly proportional to current and hence the answer.
                
                        Manju said: 
                         
                        1 decade ago
                
                In series RL circuit current is varied corresponds to frequency.
                
                        Kumaran said: 
                         
                        1 decade ago
                
                In RL circuit there is a time required to reach maximum current, so the time increases frequency will be decreases.
                
                        Tejas said: 
                         
                        1 decade ago
                
                Option A is correct answer. Voltage and frequency are directly proportional in inductive circuit. Voltage is directly proportional to current.
                
                        Firdos said: 
                         
                        9 years ago
                
                I = V/xL, I = v/wL it means, the current is inversely proportional to frequency.
                
                        GAURAV said: 
                         
                        9 years ago
                
                As frequency decreases xl decrease so that net impedance 'z' decrease so that opposition to current flow decrease hence more current flow.
                
                        Shyam said: 
                         
                        7 years ago
                
                I = v/z.
I = 1/2 * π * f * l current increases the frequency decreases.
                I = 1/2 * π * f * l current increases the frequency decreases.
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