Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 4)
4.
To increase the current in a series RL circuit, the frequency
Discussion:
7 comments Page 1 of 1.
Shyam said:
4 years ago
I = v/z.
I = 1/2 * π * f * l current increases the frequency decreases.
I = 1/2 * π * f * l current increases the frequency decreases.
GAURAV said:
6 years ago
As frequency decreases xl decrease so that net impedance 'z' decrease so that opposition to current flow decrease hence more current flow.
Firdos said:
7 years ago
I = V/xL, I = v/wL it means, the current is inversely proportional to frequency.
Tejas said:
8 years ago
Option A is correct answer. Voltage and frequency are directly proportional in inductive circuit. Voltage is directly proportional to current.
Kumaran said:
10 years ago
In RL circuit there is a time required to reach maximum current, so the time increases frequency will be decreases.
Manju said:
10 years ago
In series RL circuit current is varied corresponds to frequency.
Anonymous said:
1 decade ago
In series RL circuit voltage increases as frequency decreases but voltage is directly proportional to current and hence the answer.
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