# Electrical Engineering - RL Circuits - Discussion

Discussion Forum : RL Circuits - General Questions (Q.No. 4)

4.

To increase the current in a series

*RL*circuit, the frequencyDiscussion:

7 comments Page 1 of 1.
Shyam said:
4 years ago

I = v/z.

I = 1/2 * π * f * l current increases the frequency decreases.

I = 1/2 * π * f * l current increases the frequency decreases.

GAURAV said:
6 years ago

As frequency decreases xl decrease so that net impedance 'z' decrease so that opposition to current flow decrease hence more current flow.

Firdos said:
7 years ago

I = V/xL, I = v/wL it means, the current is inversely proportional to frequency.

Tejas said:
8 years ago

Option A is correct answer. Voltage and frequency are directly proportional in inductive circuit. Voltage is directly proportional to current.

Kumaran said:
10 years ago

In RL circuit there is a time required to reach maximum current, so the time increases frequency will be decreases.

Manju said:
10 years ago

In series RL circuit current is varied corresponds to frequency.

Anonymous said:
1 decade ago

In series RL circuit voltage increases as frequency decreases but voltage is directly proportional to current and hence the answer.

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