Electrical Engineering - RL Circuits - Discussion
Discussion Forum : RL Circuits - General Questions (Q.No. 18)
18.
When the frequency of the voltage applied to a series RL circuit is increased, the phase angle
Discussion:
3 comments Page 1 of 1.
Chip Tausch said:
1 decade ago
As f ---> 0,
The phase < of the inductor approaches pi/2
The phase < of the resistor approaches 0
As f ---> infinity
The phase < of the inductor approaches 0
The phase < of the resistor approaches pi/2
So the phase over the resistor definitely increases, but the overall phase angle will depend on what the previous phase angle was before you started increasing the frequency.
The phase < of the inductor approaches pi/2
The phase < of the resistor approaches 0
As f ---> infinity
The phase < of the inductor approaches 0
The phase < of the resistor approaches pi/2
So the phase over the resistor definitely increases, but the overall phase angle will depend on what the previous phase angle was before you started increasing the frequency.
Alaa said:
1 decade ago
I can not understand this answer.
Can you provide us equations ?
Can you provide us equations ?
Xyz said:
1 decade ago
Phase angle = tan(inverse) [2pifL/R]. So f is increase then phase angle is increase.
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