Discussion :: RL Circuits - General Questions (Q.No.18)
|Chip Tausch said: (Sep 27, 2012)|
|As f ---> 0,
The phase < of the inductor approaches pi/2
The phase < of the resistor approaches 0
As f ---> infinity
The phase < of the inductor approaches 0
The phase < of the resistor approaches pi/2
So the phase over the resistor definitely increases, but the overall phase angle will depend on what the previous phase angle was before you started increasing the frequency.
|Alaa said: (Nov 3, 2014)|
|I can not understand this answer.
Can you provide us equations ?
|Xyz said: (Jan 6, 2015)|
|Phase angle = tan(inverse) [2pifL/R]. So f is increase then phase angle is increase.|
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