Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 25)
25.
A 2 k
resistor and a 0.002 
F capacitor are in series across an ac source. Current in the circuit is 6.50 mA. The true power is
resistor and a 0.002 F capacitor are in series across an ac source. Current in the circuit is 6.50 mA. The true power isDiscussion:
4 comments Page 1 of 1.
PRANAY said:
1 decade ago
p = I^2*R
SO WE GOT THE RIGHT ANSWER
SO WE GOT THE RIGHT ANSWER
Sanju K said:
1 decade ago
P = I^2*R.
P = 6.50mA^2*2000.
P = 0.0845.
P = 84.5 mW.
P = 6.50mA^2*2000.
P = 0.0845.
P = 84.5 mW.
ROOPESH D M said:
1 decade ago
Due to capacitance OR INDUCTANCE we get reactive power (Q).
The real power (S) depends on only resistance.
S=VI=(I^2)/R.
The real power (S) depends on only resistance.
S=VI=(I^2)/R.
Flower Moon said:
10 years ago
As we know that:
P = VI.
& V = IR according to Ohm's law.
So P = (I^2)R.
P = VI.
& V = IR according to Ohm's law.
So P = (I^2)R.
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