Electrical Engineering - RC Circuits - Discussion

Discussion :: RC Circuits - General Questions (Q.No.25)

25. 

A 2 k resistor and a 0.002 F capacitor are in series across an ac source. Current in the circuit is 6.50 mA. The true power is

[A]. 84.5 mW
[B]. 845 mW
[C]. 13 mW
[D]. 130 mW

Answer: Option A

Explanation:

No answer description available for this question.

Pranay said: (Apr 27, 2012)  
p = I^2*R
SO WE GOT THE RIGHT ANSWER

Sanju K said: (May 20, 2015)  
P = I^2*R.
P = 6.50mA^2*2000.
P = 0.0845.
P = 84.5 mW.

Roopesh D M said: (Jun 18, 2015)  
Due to capacitance OR INDUCTANCE we get reactive power (Q).

The real power (S) depends on only resistance.

S=VI=(I^2)/R.

Flower Moon said: (Jan 21, 2016)  
As we know that:

P = VI.

& V = IR according to Ohm's law.

So P = (I^2)R.

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