Electrical Engineering - RC Circuits - Discussion
Discussion Forum : RC Circuits - General Questions (Q.No. 27)
27.
When the frequency of the voltage applied to a series RC circuit is decreased, the impedance
Discussion:
5 comments Page 1 of 1.
Muhammad Shoaib said:
5 years ago
Z = R-jXc
= R-j/2*π*f*C.
Now as f decrease, Xc will increase.
As a result whole impedance Z= √(R^2+Xc^2) will also increase.
= R-j/2*π*f*C.
Now as f decrease, Xc will increase.
As a result whole impedance Z= √(R^2+Xc^2) will also increase.
Rounak said:
6 years ago
Yes, the impedance would fall.
ROOPESH D M said:
1 decade ago
Xc=1/2pifc.
Z=R-JXc.
So if F decreases Xc increases. So Z=SQRT (R^2+ Xc^2) increases.
Z=R-JXc.
So if F decreases Xc increases. So Z=SQRT (R^2+ Xc^2) increases.
Manikonda malakondaiah said:
1 decade ago
Z=R-(j/fc), as f decreases, 1/fc factor increases so Z will be decreased. Correct answer is option B. Please change the option as early as possible.
Naresh goud said:
1 decade ago
Impedance(z) = R-jXc.
Xc = 1/2pifc now as frequency increases capacitive reactance(Xc) will decreases so total impedance will rise.
Xc = 1/2pifc now as frequency increases capacitive reactance(Xc) will decreases so total impedance will rise.
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