Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 10)
10.
The number 3.2 × 10–5 A expressed using a metric prefix is
Discussion:
25 comments Page 1 of 3.
Ruthis said:
2 months ago
I can't understand this please give me a brief explanation.
Amina said:
5 months ago
For getting micro A, it should be 10^-6,
So, to get 10^-6 we have to divide it by 10 i.e multiply by 10^-1.
So, if we divide by 10, to make the value the same we have to multiply by 10.
i.e 3.2 x 10^-5 x 10^ -1 x 10)= 32 x 10^-6 = 32 micro A.
So, to get 10^-6 we have to divide it by 10 i.e multiply by 10^-1.
So, if we divide by 10, to make the value the same we have to multiply by 10.
i.e 3.2 x 10^-5 x 10^ -1 x 10)= 32 x 10^-6 = 32 micro A.
(1)
Akils said:
2 years ago
0.000032 * 1000,000 = 32.
Agat said:
2 years ago
1 micro−ampere = 10 − 6 A = 1/10^6. = 0.000001
3.2 × 10–5 A = 3.2 x 1/10^5 = 0.000032.
Therefore; 3.2 x 10^-5 A= 32 micro- ampere.
3.2 × 10–5 A = 3.2 x 1/10^5 = 0.000032.
Therefore; 3.2 x 10^-5 A= 32 micro- ampere.
(1)
Ravi rathor said:
2 years ago
Anyone, Please explain this in detail to me.
(3)
Girish said:
3 years ago
This answer is not 32 µA. It's 320 ma
= 3.2*10^-5,
= 3.2*10^-5*10^-3,
= 3.2*10^-2,
= 320mA.
= 3.2*10^-5,
= 3.2*10^-5*10^-3,
= 3.2*10^-2,
= 320mA.
(7)
Anand said:
3 years ago
Anyone, Please explain this in detail.
(1)
Hamayat ullah said:
5 years ago
Please explain this question in detail.
P.neelima said:
5 years ago
I can't understand this problem please explain.
(1)
Krishna said:
6 years ago
I can't get it, please anyone explain me.
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