Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 12)
12.
When these numbers are added, (87 × 105) + (2.5 × 106), the result is
Discussion:
23 comments Page 2 of 3.
Avinash said:
1 decade ago
(87*10^5)+(2.5*10^6)
8700000+2.5000000
8700000+2500000
11200000
112*10^5
8700000+2.5000000
8700000+2500000
11200000
112*10^5
(1)
BALA said:
1 decade ago
(87+25)*10^5 = 112*10^5.
Rohit said:
1 decade ago
how its come?
Prince Janesh Unique said:
1 decade ago
Lets discuss:
87*10^5 ---------> 87*10^5.
2.5*10^6 --------> 25*10^5 (adding both).
-----------
112*10^5
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87*10^5 ---------> 87*10^5.
2.5*10^6 --------> 25*10^5 (adding both).
-----------
112*10^5
-----------
Mahesh choudhari said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Prajakta said:
1 decade ago
Thanks amit.
Iqbal singh said:
1 decade ago
Thanks Avinash.
Lalit sharma said:
9 years ago
Thnks @Amit Chandra.
Harsh said:
1 decade ago
Thanks avinash and amit.
AMIT CHANDRA JHA said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
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