Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 12)
12.
When these numbers are added, (87 × 105) + (2.5 × 106), the result is
Discussion:
23 comments Page 1 of 3.
Rohit said:
1 decade ago
how its come?
Avinash said:
1 decade ago
(87*10^5)+(2.5*10^6)
8700000+2.5000000
8700000+2500000
11200000
112*10^5
8700000+2.5000000
8700000+2500000
11200000
112*10^5
(1)
M.venkatesan said:
1 decade ago
It is very useful to improve our knowledge.
Suresh said:
1 decade ago
(87*10^5)+(2.5*10^6)
sol:
(87*10^5)+(25*10^5)
(87+25)10^5
112*10^5
sol:
(87*10^5)+(25*10^5)
(87+25)10^5
112*10^5
(2)
Anand said:
1 decade ago
Thanks Avanish & Suresh
AMIT CHANDRA JHA said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Harsh said:
1 decade ago
Thanks avinash and amit.
Iqbal singh said:
1 decade ago
Thanks Avinash.
Prajakta said:
1 decade ago
Thanks amit.
Mahesh choudhari said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
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