Electrical Engineering - Quantities and Units - Discussion
Discussion Forum : Quantities and Units - General Questions (Q.No. 12)
12.
When these numbers are added, (87 × 105) + (2.5 × 106), the result is
Discussion:
23 comments Page 1 of 3.
Prince Janesh Unique said:
1 decade ago
Lets discuss:
87*10^5 ---------> 87*10^5.
2.5*10^6 --------> 25*10^5 (adding both).
-----------
112*10^5
-----------
87*10^5 ---------> 87*10^5.
2.5*10^6 --------> 25*10^5 (adding both).
-----------
112*10^5
-----------
AMIT CHANDRA JHA said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Mahesh choudhari said:
1 decade ago
It is simple...Just Balance the Power..i.e (2.5*10^6)==(25*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Now we have (87*10^5)+(25*10^5)=(87+25)*10^5=(112*10^5)
Vandan said:
8 years ago
Take the common 10^5 i.e
10^5 [(87 x 1) + (2.5 x 10)].
10^5 [(87+25].
10^5 [112].
Answer is 112 x 10^5.
10^5 [(87 x 1) + (2.5 x 10)].
10^5 [(87+25].
10^5 [112].
Answer is 112 x 10^5.
(33)
Avinash said:
1 decade ago
(87*10^5)+(2.5*10^6)
8700000+2.5000000
8700000+2500000
11200000
112*10^5
8700000+2.5000000
8700000+2500000
11200000
112*10^5
(1)
Suresh said:
1 decade ago
(87*10^5)+(2.5*10^6)
sol:
(87*10^5)+(25*10^5)
(87+25)10^5
112*10^5
sol:
(87*10^5)+(25*10^5)
(87+25)10^5
112*10^5
(2)
THANGADURAI said:
1 decade ago
8700000 + 2.5000000.
8700000 + 2500000.
11200000.
112*10^5.
8700000 + 2500000.
11200000.
112*10^5.
(1)
Vamshi said:
9 years ago
(87 * 10^5) + (2.5 * 10^6) = 11200000 = 112 * 10^5.
(6)
M.venkatesan said:
1 decade ago
It is very useful to improve our knowledge.
Crisy said:
3 years ago
Thanks all for explaining the answer.
(1)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers