Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 14)
14.
Five 100
resistors are connected in parallel. If one resistor is removed, the total resistance is

Answer: Option
Explanation:
1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 1/R = 1/100 + 1/100 + 100 + 1/100 1/R = 4/100 1/R = 1/25 Therefore R = 25 ohm.
Discussion:
2 comments Page 1 of 1.
Ajh said:
9 years ago
If the equal value of resistances is connected in parallel, then the effective resistance of parallel combination is given by.
Suppose n branches have the resistances R then,
Re = R/n.
Suppose n branches have the resistances R then,
Re = R/n.
Rud Sarvi said:
9 years ago
Re = R/n.
Step1:
5 registers of 100 Ω.
So Re = 100/5 = 20 Ω.
Step2:
1 removed so 100/4 = 25 Ω.
Step1:
5 registers of 100 Ω.
So Re = 100/5 = 20 Ω.
Step2:
1 removed so 100/4 = 25 Ω.
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