Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 14)
14.
Five 100 
resistors are connected in parallel. If one resistor is removed, the total resistance is
resistors are connected in parallel. If one resistor is removed, the total resistance is25
500
100
20
Answer: Option
Explanation:
1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4 1/R = 1/100 + 1/100 + 100 + 1/100 1/R = 4/100 1/R = 1/25 Therefore R = 25 ohm.
Discussion:
2 comments Page 1 of 1.
Rud Sarvi said:
9 years ago
Re = R/n.
Step1:
5 registers of 100 Ω.
So Re = 100/5 = 20 Ω.
Step2:
1 removed so 100/4 = 25 Ω.
Step1:
5 registers of 100 Ω.
So Re = 100/5 = 20 Ω.
Step2:
1 removed so 100/4 = 25 Ω.
Ajh said:
9 years ago
If the equal value of resistances is connected in parallel, then the effective resistance of parallel combination is given by.
Suppose n branches have the resistances R then,
Re = R/n.
Suppose n branches have the resistances R then,
Re = R/n.
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