Electrical Engineering - Parallel Circuits - Discussion

Whatever may be a count of the resistance in parallel.
That's not important here ...

here, they were given total resistance and total voltage and all the resistance is connected in parallel.
Let's make it simple..voltage across each resistance is the same (because of the parallel circuit)

Total voltage = voltage drop in anyone of the resistance part.

Total current * Total resistance = Individual current* particular resistance value,
50 *120 = x *270.
X = (50 *120)/270.
X ~ 22mA.

R1 = 50 ohm.
I1 = 120 mA.
V = I*R(50*120 = 6000 mV).
I2 = V/R2 = 6000/270
= 22.22 mA.

I think we can do by ohm's also. In first case we know resistance value and current by this we can find voltage value. In second case we we know resistance value and we already find voltage in first case by using these we can find current.

Ex : Case 1:

V = IR.
V = 50*120 ma.
V = 6 volt.

Case 2:

I = v/r.
I = 6/270.
I = 22 ma.

Let me know this method is correct or not.

I can't understand. Someone explain me clearly.

120 ma * 50/270 = 22ma

As the resistances are in parallel so,
Req = R1 * R2/(R1+R2).
So from here, 50 = 270 * R2/(270+R2).
R2=61.3ohm.
Now, using the current division rule for I, we get;
I2 = I * (R2/R2+R1).
I2 = 22ma.

According to current div rule.

Current= (total current*total resistance) /particular resistance.

Thanks raja.

Acc to CDR, current = (particular resistance * total current)/total resistance..

Can be explain anybody ?