# Electrical Engineering - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)

2.

The total resistance of a parallel circuit is 50 . If the total current is 120 mA, the current through the 270 resistor that makes up part of the parallel circuit is approximately

Discussion:

15 comments Page 1 of 2.
Raguram said:
8 months ago

Whatever may be a count of the resistance in parallel.

That's not important here ...

here, they were given total resistance and total voltage and all the resistance is connected in parallel.

Let's make it simple..voltage across each resistance is the same (because of the parallel circuit)

Total voltage = voltage drop in anyone of the resistance part.

Total current * Total resistance = Individual current* particular resistance value,

50 *120 = x *270.

X = (50 *120)/270.

X ~ 22mA.

That's not important here ...

here, they were given total resistance and total voltage and all the resistance is connected in parallel.

Let's make it simple..voltage across each resistance is the same (because of the parallel circuit)

Total voltage = voltage drop in anyone of the resistance part.

Total current * Total resistance = Individual current* particular resistance value,

50 *120 = x *270.

X = (50 *120)/270.

X ~ 22mA.

(2)

Parampal sehgal said:
1 decade ago

120 ma * 50/270 = 22ma

(1)

Puja said:
7 years ago

I can't understand. Someone explain me clearly.

(1)

Raja said:
1 decade ago

According to current div rule.

Current= (total current*total resistance) /particular resistance.

Current= (total current*total resistance) /particular resistance.

Deva said:
1 decade ago

Thanks raja.

Mohana.. said:
1 decade ago

Acc to CDR, current = (particular resistance * total current)/total resistance..

Dilip said:
1 decade ago

Can be explain anybody ?

Ramesh said:
1 decade ago

Total Resistance=50

R1 and R2 are in parallel.

(1/R1)+(1/R2)=(1/50)

R1=270 ohms (given)

R2=61.36

R2=R1/(m-1)

where m=(Total Current/Current through 270 ohms)

Using above formula find out the current through 270 ohms...

R1 and R2 are in parallel.

(1/R1)+(1/R2)=(1/50)

R1=270 ohms (given)

R2=61.36

R2=R1/(m-1)

where m=(Total Current/Current through 270 ohms)

Using above formula find out the current through 270 ohms...

Sarkars said:
1 decade ago

Concept of raja and ramesh wrong, Sehegal is correct.

Try this way:

Total voltage = 50ohm * 120mA = 6 V

Current through 270 ohm resistor = 6 V/270 ohm = 22 mA

Try this way:

Total voltage = 50ohm * 120mA = 6 V

Current through 270 ohm resistor = 6 V/270 ohm = 22 mA

MOHIT RAJHANS said:
1 decade ago

R1 and R2 are in parallel,

So (R1) * (R2) / (R1+R2) =50.

R1 = 270 ohm, R2 is unknown.

We get R2 = 61. 3 ohms.

Now using current division rule we get,

I2 = (Total current) * (R2/R1+R2).

= 120* (61/331).

= 22 mA.

That is the required answer, hope you people understand.

So (R1) * (R2) / (R1+R2) =50.

R1 = 270 ohm, R2 is unknown.

We get R2 = 61. 3 ohms.

Now using current division rule we get,

I2 = (Total current) * (R2/R1+R2).

= 120* (61/331).

= 22 mA.

That is the required answer, hope you people understand.

Post your comments here:

Your comments will be displayed after verification.

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers

© IndiaBIX™ Technologies