Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)
2.
The total resistance of a parallel circuit is 50 
. If the total current is 120 mA, the current through the 270 resistor that makes up part of the parallel circuit is approximately
. If the total current is 120 mA, the current through the 270 resistor that makes up part of the parallel circuit is approximatelyDiscussion:
16 comments Page 1 of 2.
Raja said:
1 decade ago
According to current div rule.
Current= (total current*total resistance) /particular resistance.
Current= (total current*total resistance) /particular resistance.
Deva said:
1 decade ago
Thanks raja.
Mohana.. said:
1 decade ago
Acc to CDR, current = (particular resistance * total current)/total resistance..
Dilip said:
1 decade ago
Can be explain anybody ?
Ramesh said:
1 decade ago
Total Resistance=50
R1 and R2 are in parallel.
(1/R1)+(1/R2)=(1/50)
R1=270 ohms (given)
R2=61.36
R2=R1/(m-1)
where m=(Total Current/Current through 270 ohms)
Using above formula find out the current through 270 ohms...
R1 and R2 are in parallel.
(1/R1)+(1/R2)=(1/50)
R1=270 ohms (given)
R2=61.36
R2=R1/(m-1)
where m=(Total Current/Current through 270 ohms)
Using above formula find out the current through 270 ohms...
Parampal sehgal said:
1 decade ago
120 ma * 50/270 = 22ma
(1)
Sarkars said:
1 decade ago
Concept of raja and ramesh wrong, Sehegal is correct.
Try this way:
Total voltage = 50ohm * 120mA = 6 V
Current through 270 ohm resistor = 6 V/270 ohm = 22 mA
Try this way:
Total voltage = 50ohm * 120mA = 6 V
Current through 270 ohm resistor = 6 V/270 ohm = 22 mA
MOHIT RAJHANS said:
1 decade ago
R1 and R2 are in parallel,
So (R1) * (R2) / (R1+R2) =50.
R1 = 270 ohm, R2 is unknown.
We get R2 = 61. 3 ohms.
Now using current division rule we get,
I2 = (Total current) * (R2/R1+R2).
= 120* (61/331).
= 22 mA.
That is the required answer, hope you people understand.
So (R1) * (R2) / (R1+R2) =50.
R1 = 270 ohm, R2 is unknown.
We get R2 = 61. 3 ohms.
Now using current division rule we get,
I2 = (Total current) * (R2/R1+R2).
= 120* (61/331).
= 22 mA.
That is the required answer, hope you people understand.
Mrakovic said:
1 decade ago
Ri = 50ohm.
Ii = 120 mA = 0.120A.
R1 = 270 ohm.
U = Ii*Ri = 0.120*50 = 6V.
I1 = U/R1 = 6/270 = 0.022A = 22 mA.
Ii = 120 mA = 0.120A.
R1 = 270 ohm.
U = Ii*Ri = 0.120*50 = 6V.
I1 = U/R1 = 6/270 = 0.022A = 22 mA.
Shiva said:
1 decade ago
R1 = 50 ohm.
I1 = 120 mA.
V = I*R(50*120 = 6000 mV).
I2 = V/R2 = 6000/270
= 22.22 mA.
I1 = 120 mA.
V = I*R(50*120 = 6000 mV).
I2 = V/R2 = 6000/270
= 22.22 mA.
(3)
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