# Electrical Engineering - Parallel Circuits - Discussion

Discussion Forum : Parallel Circuits - General Questions (Q.No. 2)

2.

The total resistance of a parallel circuit is 50 . If the total current is 120 mA, the current through the 270 resistor that makes up part of the parallel circuit is approximately

Discussion:

16 comments Page 1 of 2.
Raja said:
1 decade ago

According to current div rule.

Current= (total current*total resistance) /particular resistance.

Current= (total current*total resistance) /particular resistance.

Deva said:
1 decade ago

Thanks raja.

Mohana.. said:
1 decade ago

Acc to CDR, current = (particular resistance * total current)/total resistance..

Dilip said:
1 decade ago

Can be explain anybody ?

Ramesh said:
1 decade ago

Total Resistance=50

R1 and R2 are in parallel.

(1/R1)+(1/R2)=(1/50)

R1=270 ohms (given)

R2=61.36

R2=R1/(m-1)

where m=(Total Current/Current through 270 ohms)

Using above formula find out the current through 270 ohms...

R1 and R2 are in parallel.

(1/R1)+(1/R2)=(1/50)

R1=270 ohms (given)

R2=61.36

R2=R1/(m-1)

where m=(Total Current/Current through 270 ohms)

Using above formula find out the current through 270 ohms...

Parampal sehgal said:
1 decade ago

120 ma * 50/270 = 22ma

(1)

Sarkars said:
1 decade ago

Concept of raja and ramesh wrong, Sehegal is correct.

Try this way:

Total voltage = 50ohm * 120mA = 6 V

Current through 270 ohm resistor = 6 V/270 ohm = 22 mA

Try this way:

Total voltage = 50ohm * 120mA = 6 V

Current through 270 ohm resistor = 6 V/270 ohm = 22 mA

MOHIT RAJHANS said:
1 decade ago

R1 and R2 are in parallel,

So (R1) * (R2) / (R1+R2) =50.

R1 = 270 ohm, R2 is unknown.

We get R2 = 61. 3 ohms.

Now using current division rule we get,

I2 = (Total current) * (R2/R1+R2).

= 120* (61/331).

= 22 mA.

That is the required answer, hope you people understand.

So (R1) * (R2) / (R1+R2) =50.

R1 = 270 ohm, R2 is unknown.

We get R2 = 61. 3 ohms.

Now using current division rule we get,

I2 = (Total current) * (R2/R1+R2).

= 120* (61/331).

= 22 mA.

That is the required answer, hope you people understand.

Mrakovic said:
1 decade ago

Ri = 50ohm.

Ii = 120 mA = 0.120A.

R1 = 270 ohm.

U = Ii*Ri = 0.120*50 = 6V.

I1 = U/R1 = 6/270 = 0.022A = 22 mA.

Ii = 120 mA = 0.120A.

R1 = 270 ohm.

U = Ii*Ri = 0.120*50 = 6V.

I1 = U/R1 = 6/270 = 0.022A = 22 mA.

Shiva said:
10 years ago

R1 = 50 ohm.

I1 = 120 mA.

V = I*R(50*120 = 6000 mV).

I2 = V/R2 = 6000/270

= 22.22 mA.

I1 = 120 mA.

V = I*R(50*120 = 6000 mV).

I2 = V/R2 = 6000/270

= 22.22 mA.

(3)

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