Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 6)
6.
If there are a total of 120 mA into a parallel circuit consisting of three branches, and two of the branch currents are 40 mA and 10 mA, the third branch current is
Discussion:
3 comments Page 1 of 1.
Swathi said:
1 decade ago
In parallel circuits the current is dividing, here total current is 120, it contains 3 branches, 1st branch current is 40mA, 2nd branch current is 10mA, then the remaining 3rd branch current is 70mA.
Amit said:
1 decade ago
In parallel circuits the current is dividing,
I = i1+i2+i3.
So 120 = 40+10+i3.
So i3 = 120-50.
i3 = 70ma.
I = i1+i2+i3.
So 120 = 40+10+i3.
So i3 = 120-50.
i3 = 70ma.
(1)
Anand said:
1 decade ago
Total Current=sum of the branch current,
120=40+10+I,
I=120-(40+10)=70 ma
120=40+10+I,
I=120-(40+10)=70 ma
(1)
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