Electrical Engineering - Parallel Circuits - Discussion

Discussion :: Parallel Circuits - General Questions (Q.No.6)

6. 

If there are a total of 120 mA into a parallel circuit consisting of three branches, and two of the branch currents are 40 mA and 10 mA, the third branch current is

[A]. 50 mA
[B]. 70 mA
[C]. 120 mA
[D]. 40 mA

Answer: Option B

Explanation:

No answer description available for this question.

Anand said: (Jul 26, 2011)  
Total Current=sum of the branch current,
120=40+10+I,
I=120-(40+10)=70 ma

Swathi said: (Apr 12, 2014)  
In parallel circuits the current is dividing, here total current is 120, it contains 3 branches, 1st branch current is 40mA, 2nd branch current is 10mA, then the remaining 3rd branch current is 70mA.

Amit said: (Apr 14, 2015)  
In parallel circuits the current is dividing,

I = i1+i2+i3.

So 120 = 40+10+i3.

So i3 = 120-50.

i3 = 70ma.

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