Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 5)
5.
When a 1.6 k
resistor and a 120 resistor are connected in parallel, the total resistance is
resistor and a 120 resistor are connected in parallel, the total resistance isgreater than 1.6 k
greater than 120 but less than 1.6 k
but less than 1.6 kless than 120 but greater than 100
but greater than 100 less than 100
Discussion:
5 comments Page 1 of 1.
Anand said:
1 decade ago
Can anybody explain about the answer ?
Jinal said:
1 decade ago
1/R=1/R1+1/R2
=1/1600+1/120
=(120+1600)/(120*1600)
so that,
R=111.63
That is less than 120 ohm and greater than 100 ohm.
=1/1600+1/120
=(120+1600)/(120*1600)
so that,
R=111.63
That is less than 120 ohm and greater than 100 ohm.
Saravanan said:
1 decade ago
R = R1R2/ (R1+R2).
R = 1600*120/ (1600+120).
R = 111.62.
R = 1600*120/ (1600+120).
R = 111.62.
(1)
Madhusudana B R said:
10 years ago
In parallel circuit, if 10 no of different rating resistance connected parallel in that total resistance should be less than smaller value resistance of the parallel circuit. So you can consider less than 120 ohms as your answer.
Ali Assad Mir said:
3 years ago
In Parallel combination, the equivalent resistance is less than the smallest resistance but to calculate whether resistance is greater than 100 ohms or not we have to do the said calculations R = R1R2/ (R1+R2).
R = 1600 * 120/ (1600+120).
R = 111.62.
R = 1600 * 120/ (1600+120).
R = 111.62.
(1)
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