Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k
of resistance, what is the voltage drop across the resistor?
of resistance, what is the voltage drop across the resistor?Discussion:
60 comments Page 4 of 6.
Benard Istifanus said:
6 years ago
Thanks all for explaining it.
Naveen said:
1 decade ago
Dear Friends,,
Its very easy to find the answer in Exams...as the thing is Resistor never consumes the type of current..it always gives out what ever it have. So no use of calulating in this way...
Just it is produsing 11 and I is 75*10^-6
ie
.75*11=8025
Its very easy to find the answer in Exams...as the thing is Resistor never consumes the type of current..it always gives out what ever it have. So no use of calulating in this way...
Just it is produsing 11 and I is 75*10^-6
ie
.75*11=8025
Anil said:
1 decade ago
v=i*r
Punithajothi said:
1 decade ago
v=i*r its simple
Vshree said:
1 decade ago
According to Ohm's Law: V = I x R
Joy jumbo itah said:
1 decade ago
Given that;
I=750microamps ie;750/1000 =0.750A
R=11kil0 ohms
therefore V = I*R from ohm's law
V = 0.75*11=8.25v
It's right
I=750microamps ie;750/1000 =0.750A
R=11kil0 ohms
therefore V = I*R from ohm's law
V = 0.75*11=8.25v
It's right
4getfull said:
1 decade ago
Regarding the ohms wouldn't k represent 1,000, if not what is the abbreviation represent? or did i just get it it by realizing the microamps has already been converted by devising by 1,000 and thats why 11 works instead of 11,000
Nju said:
1 decade ago
According to my concept too 11kilo ohms must be 11000ohms.
So do I disagree with the ans i.e 8. 25v.
So do I disagree with the ans i.e 8. 25v.
M.Nedunchezhian said:
1 decade ago
Ya I have same doubt like @4getfull.
M.Nedunchezhian said:
1 decade ago
All above methods are wrong.
1 microamphere = 10^-6 Amphere.
Therefore, 750 microamphere = 750/1000000=0.00075 Amphere.
11 kiloohm = 11000 ohms.
V=I*R
V=0.00075*11000=8.25V.
1 microamphere = 10^-6 Amphere.
Therefore, 750 microamphere = 750/1000000=0.00075 Amphere.
11 kiloohm = 11000 ohms.
V=I*R
V=0.00075*11000=8.25V.
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