Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k of resistance, what is the voltage drop across the resistor?
8.25 V
82.5 V
14.6 V
146 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
60 comments Page 4 of 6.

Manthar ali said:   1 decade ago
V = IR.
V = 750*10^-6*11*10^3.
V = 750*10^-3*11=8250.

So V = 8250*10^-3.
V = 8.250 V.

Nagaraja m said:   1 decade ago
V = ?
i = 750 UA, = 0.750 A.
R = 11 K ohms = 1100.

WKT, V = iR.

So, = 0.750*1100 = 8.25.

PAMMI said:   1 decade ago
V = IR.
V = 0.00075*11000.
V = 8.25.

Because,
1 MICRO AMP = 1000000.
1 KILLO OHMS = 1000.

Waiswa mathius said:   10 years ago
From ohm's law, V=IR where are is the resistance of the material in Ohms, V is the voltage supplied to the appliance in volts and I the current flowing in Amperes.

V=IR.

1 micro amperes = 0.000001 A.

750 micro amperes = 750*0.000001.

= 0.00075 A.

1 kilo ohm = 1000 ohms.
11 kilo ohm = 11*1000.
= 11000 ohms.

Therefor, V = 0.00075*11000 = 8. 5 V.

Rahul chouhan said:   10 years ago
Ohms.

V = IR.

I = 750 UA.

R = 11 kilo ohm.

V = 750*11.

V = 8250/1000.

V = 8.25.

Jayesh J. Joshi said:   9 years ago
I = 750 micro amp.
= 0.00075 amp.
= 75/1000000 amp.

R = 11 kilo ohm.
= 11 * 1000 ohm.
= 110000 ohm.

V = IR.
= 75/1000000 * 110000.
= 8.25 VOLT => ANS.

Imrosekhan said:   9 years ago
Here, v = ir.

Small idea is micro is powerten(-6) & kilo is powerten(--3).
750 * powerten(-6) =0.00075,
v = 0.00075 * 110000 = 8.25.

Chisom rapheal mark said:   8 years ago
V = IR.
I = 750uA = 750/1000000 = 0.00075A,
R = 11kohms = 11 * 1000 = 11000ohms,
.'.V = 0.00075*11000,
V = 8.25v.

Nans said:   8 years ago
Thanks @Nedunchezhian.

ABHINANDAN Asd said:   8 years ago
Thanks for your solution @Nedunchezhian.


Post your comments here:

Your comments will be displayed after verification.