Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 2)
2.
If 750 µA is flowing through 11 k
of resistance, what is the voltage drop across the resistor?
of resistance, what is the voltage drop across the resistor?Discussion:
60 comments Page 2 of 6.
Krunal Shah said:
1 decade ago
Thank u 4 giving explanation
Gobimohanraj said:
1 decade ago
Nice and Correct Explanation Mr.M.Neduchezhian
Prabu said:
1 decade ago
Mr.M.Neduchezhian vry crt & nice explanation.
Anand said:
1 decade ago
I=750X10^-6 A,
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3)
V=750X11X10^-3
V=0.75X11=8.25 V
R=11X10^3 ,
V=I*R=750X10^-6*11X10^-3=750X11X(10^-6+10^3)
V=750X11X10^-3
V=0.75X11=8.25 V
Kalpesh said:
1 decade ago
Mr. M. Neduchezhian is right & nice explanation.
Thanks for given right answer.
Thanks for given right answer.
Jagpreet said:
1 decade ago
8.25 is actual supply votage and its not the drop across 11 kohm resistor.
Naveen said:
1 decade ago
Dear Friends,,
Its very easy to find the answer in Exams...as the thing is Resistor never consumes the type of current..it always gives out what ever it have. So no use of calulating in this way...
Just it is produsing 11 and I is 75*10^-6
ie
.75*11=8025
Its very easy to find the answer in Exams...as the thing is Resistor never consumes the type of current..it always gives out what ever it have. So no use of calulating in this way...
Just it is produsing 11 and I is 75*10^-6
ie
.75*11=8025
Cyko said:
1 decade ago
@ M. Nedunchezhian very good explained thank you.
Jagdish Raval said:
1 decade ago
What is the Difference between actual Voltage supply & Voltage Drop?
Srinivas said:
1 decade ago
@jag
Actual voltage supply is the supply voltage giving by the source, voltage drop is the fall in the voltage because of resistance of the resistor in circuit.
Actual voltage supply is the supply voltage giving by the source, voltage drop is the fall in the voltage because of resistance of the resistor in circuit.
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