Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 7)
7.
What is the voltage source for a circuit carrying 2 A of current through a 36 
resistor?
resistor?Discussion:
8 comments Page 1 of 1.
Mani said:
1 decade ago
It is simple .
v=i*r
=2*36
=72v
v=i*r
=2*36
=72v
Suraj said:
1 decade ago
Ya according to ohm's law.
V = IR
= 2*36 = 72
V = IR
= 2*36 = 72
J.venkatesh said:
1 decade ago
According to ohms law, V=IR
Where V=IR
V = 36*2.
V = 72 Volts.
Where V=IR
V = 36*2.
V = 72 Volts.
Jayadhar said:
1 decade ago
Assuming Temperature is constant, By OHM'S law V = IR.
V = 2*36.
= 72.
V = 2*36.
= 72.
Ravi teja said:
9 years ago
2 * 36 = 72.
Rohit sahu said:
7 years ago
According to ohms law, V=I*R
I=2A.
R=36,
V=2*36=72v.
I=2A.
R=36,
V=2*36=72v.
MANI KRISHNA said:
3 years ago
V = IR
V = ?
I = 2A
R = 36
V = 2*36 = 72V.
V = ?
I = 2A
R = 36
V = 2*36 = 72V.
Johnlerr Espenoza said:
2 years ago
V = I×R.
V = 2×36.
= 72V.
V = 2×36.
= 72V.
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