Electrical Engineering - Ohm's Law - Discussion

Discussion :: Ohm's Law - General Questions (Q.No.7)

7. 

What is the voltage source for a circuit carrying 2 A of current through a 36 resistor?

[A]. 1.8 V
[B]. 18 V
[C]. 7.2 V
[D]. 72 V

Answer: Option D

Explanation:

No answer description available for this question.

Mani said: (Mar 13, 2011)  
It is simple .

v=i*r
=2*36
=72v

Suraj said: (Sep 20, 2011)  
Ya according to ohm's law.

V = IR

= 2*36 = 72

J.Venkatesh said: (Oct 14, 2012)  
According to ohms law, V=IR

Where V=IR
V = 36*2.
V = 72 Volts.

Jayadhar said: (Sep 22, 2013)  
Assuming Temperature is constant, By OHM'S law V = IR.

V = 2*36.

= 72.

Ravi Teja said: (Jan 16, 2017)  
2 * 36 = 72.

Rohit Sahu said: (Aug 19, 2018)  
According to ohms law, V=I*R
I=2A.
R=36,
V=2*36=72v.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.