Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 7 of 11.
Sibo mondolo said:
1 decade ago
We known that, *according to ohm's law R = V/I =110/3.5 = 31.42 ohm.
O p gautam said:
1 decade ago
Resistance may not be measured in decimal. So answer in 31 ohm is correct.
Dave Mudra said:
1 decade ago
Yes, its true.
Real equation is V = I*R.
According above related answer the equation is R = V/I.
Real equation is V = I*R.
According above related answer the equation is R = V/I.
Pradeep kumar saw said:
1 decade ago
We Know that,
R = V/I.
Given that,
V = 110 Volt AND I = 3.5A.
So,
R = 110/3.5 = 31.4 OHM.
R = V/I.
Given that,
V = 110 Volt AND I = 3.5A.
So,
R = 110/3.5 = 31.4 OHM.
Jitendra Behera said:
1 decade ago
We know that R=V/I.
R=110/3. 5=31. 4ohm.
Ans- [D]. 31ohm.
R=110/3. 5=31. 4ohm.
Ans- [D]. 31ohm.
RAVI PRAKASH said:
1 decade ago
According to ohms law,
R=V/I.
So R= 1103.5
= 31.4 ohms.
So Answer is option D.
R=V/I.
So R= 1103.5
= 31.4 ohms.
So Answer is option D.
Prasanth said:
1 decade ago
According to Ohm's law V=IR.
But we need 'R'.
So bring the I to this side then it will be divided by V,
As given below,
R=V(110)/I(3.5)
R=31.4 ohms.
But we need 'R'.
So bring the I to this side then it will be divided by V,
As given below,
R=V(110)/I(3.5)
R=31.4 ohms.
Sagar said:
1 decade ago
The ohms law state in a close circuit the strength of current flowing throw a solid conductor at constant temperature is directly proportional to the voltage across the conductor and inversely proportional to the resistance.
So. I = V/R.
=110/3.5 = 31.42 ohm.
So. I = V/R.
=110/3.5 = 31.42 ohm.
Satish.J said:
1 decade ago
According to Ohm's law,
Volatage is directly proportional to Current.
i.e. V=IR
R=V/I=110/3.5=31.428 ohms
Volatage is directly proportional to Current.
i.e. V=IR
R=V/I=110/3.5=31.428 ohms
Kovvuru hussenaiah said:
1 decade ago
Yes, According to problem voltage(v) is 110v and Current(I)=3.5A.
Then R=V/I=110/3.5=31.42 then approximately=31ohm.
Then R=V/I=110/3.5=31.42 then approximately=31ohm.
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