Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 5 of 11.

Rupesh said:   1 decade ago
Why not the approximate answer is 31.1.

Bipab said:   1 decade ago
Given that,

V = 110.
I = 3.5.
R = ?

According to ohms law V = IR:

R = V/I.

= 110/3.5 = 31.42 = 31.

Abdul Rauf Ansari said:   1 decade ago
Given:

V = 110 volt.
I = 3.5 amp.
R = ?

We know that:

According to ohm's law:

I = V/R.
V = IR.
R = V/I.

=110/3.5.
=31.428.

Hence answer is 31 ohm.

Malhar Kulkarni said:   1 decade ago
We know that Resistance = Potential difference/strength of current.

R = V/I.
= 110/3.5.
= 31.428.

Rounded off,
R = 31 ohms.

Ram Gopal Joshi said:   1 decade ago
Hi all,

Please give the good definition of electric traction and formula of resonance frequency in series and parallel connection.

SHAKRU JARPULA said:   1 decade ago
We know that from ohm's law.

V = IR.

Given, R=110/31.5 = 31.428

R = 31

Negi said:   1 decade ago
Well 32 ohms would be right cause it's coming 31.428 so round off 32 ohm.

AVATAR BEHERA said:   1 decade ago
R = V/I.

R = 110/3.5 = 31.428.

Appro = 31.

V k singh said:   1 decade ago
As we know that from ohms law,
V = IR.

GIVEN,
V = 110V.
I = 3.5A.

SO R=V/I.
R=110/3.5 = 31.42 ohm.
i.e 31 ohm.

LATHA G said:   1 decade ago
By using for ohms law.

Given:
R = V/I.

SO R = 110/3.5 = 31.42.

ANSWER: 31 OHM.


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