Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 3 of 11.

Ankita said:   2 years ago
Given data
V = 110 volt.
I = 3.5 A.
We know that;
According to Ohm's law-
V = IR.
So, R = V/I
R = 110/3.5
R = 31.4 Ohm.
(5)

Ram Gopal Joshi said:   1 decade ago
Hi all,

Please give the good definition of electric traction and formula of resonance frequency in series and parallel connection.

BALA MURUGAN M said:   2 years ago
Ohm's Law firm v = IR.
Then R = V/I.

Given;
V = 110v.
I = 3.5A.
Therefore
R = 110/3.5 = 31.428.
So, the given answer is correct.
(8)

Shobhana said:   1 decade ago
Yes its correct.

By using the ohm's law we get,
R = V/I.

Therefore;- R = 110/3.5.
= 31.42 ohm.

Answer: 31 ohm.

Pavankumar said:   8 years ago
From the given question, it is related to ohm's law V=IR.
then,
from the question, V=110V and I=3.5A.
R=V/A=110/3.5=31.42=31.

Lakshman said:   1 decade ago
At constant temperature Current flowing through the conductor is directly proportional to the applied voltage.
Formula;
I=V/R

Malhar Kulkarni said:   1 decade ago
We know that Resistance = Potential difference/strength of current.

R = V/I.
= 110/3.5.
= 31.428.

Rounded off,
R = 31 ohms.

Jayaraj.R said:   5 years ago
Ohm's Law firm v = IR.
Then R=V/I

Given

V = 110v.
I = 3.5A.
Therefore R = 110/3.5 = 31.428.
So the given answer is correct.
(7)

Kovvuru hussenaiah said:   1 decade ago
Yes, According to problem voltage(v) is 110v and Current(I)=3.5A.

Then R=V/I=110/3.5=31.42 then approximately=31ohm.

Siva nanda said:   1 decade ago
Ohms law V=IR.

Then R=V/I.

Given,

V=110v.

I=3.5A

Therfore R=110/3.5=31.428.

So the given answer is correct.


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