Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385
38.5
3.1
31
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
102 comments Page 3 of 11.

M.NARENDRA said:   1 decade ago
According to ohm's law
V=IR =>R=V/I
=>R=110/3.5
R=31.4

HARI said:   1 decade ago
R=V/I
GIVEN:
VOLTAGE(V)=110V
CURRENT(I)=3.5A
RESISTANCE(R)=V/I=110/3.5\
ANS=31.42~31

ASHISH KHAN said:   1 decade ago
YES, R=V/I

=110/3.5
= 31OHM.

Sundaram.A said:   1 decade ago
R=V/I
=110/3.5
=31.4~31ohm

MOHAN said:   1 decade ago
Yes according to ohms law
V = IR
R = V/I
= 110/3.5
= 31 ohm

Surya said:   1 decade ago
Ohms law is are proportional to I inversely to V at content physical parameters like temperature and stress on conductor etc. It is right.

Elavendhan Durai said:   1 decade ago
Voltege=110v
Current=3.5A
According to the ohms law V = IR
110 = 3.5*R
R = 31 Ohm

JEYA SELVAM.P said:   1 decade ago
V=IR.
V=110V
I=3.5A
R=?
R=V/I
R=110/3.5
R=31.4
R=31ohm.

Arun said:   1 decade ago
V = IR.

R = V/I.

R = 110 / 3.5.

R = 31.42 ohm.

Sangeetha said:   1 decade ago
According to ohms law.

V=IR.
Therefore.
R=V/I.

R=110/3.5.

=31.4 ohms.


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