Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 1)
1.
An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately
385 
38.5
3.1
31
Discussion:
102 comments Page 3 of 11.
Sujin adhikari said:
9 years ago
Under a constant physical condition (i.e temperature remains constant) current flowing through the conductor is directly proportional to voltage or (potential different) applied across its end.
Magesh said:
9 years ago
Solve it by using ohm' law.
Raj vendra said:
9 years ago
According to ohm'law v=IR.
R = v/I.
R = v/I.
Imrosekhan said:
9 years ago
According to ohm's law v = IR.
Here we have to find resistance so, R = V/I.
Substitute those values=110/3.5 = 31.42.
But here they are taken as round figure value i.e 31.
Here we have to find resistance so, R = V/I.
Substitute those values=110/3.5 = 31.42.
But here they are taken as round figure value i.e 31.
Bhushan said:
9 years ago
What is the answer if there will be another option as. 31.5?
Narendra Patil said:
9 years ago
Ohms law states that at constant temperature the current flowing through the conductor is directly proportional to potential different between the two end of the conductor.
That is V = IR.
That is V = IR.
JAGANNATH said:
9 years ago
According to ohm's law V = IR.
Then, I = V/R.
R = 110/3.5 = 31.4285.
Then, I = V/R.
R = 110/3.5 = 31.4285.
Sarath said:
9 years ago
According to Ohm's law:
V = IR,
R = V/I,
R = 110/3.5,
R = 31.42.
V = IR,
R = V/I,
R = 110/3.5,
R = 31.42.
Mukesh Kumar Ghotra bemoth said:
9 years ago
V = lR.
R = v\l.
V = 110 v.
I = 3.5 A.
R =110\3.5 = 31.4 ohm.
R = v\l.
V = 110 v.
I = 3.5 A.
R =110\3.5 = 31.4 ohm.
Srinivas said:
9 years ago
V = IR.
V = 110.
I = 3.5.
R = V/I = 110/3.5 = 31.
V = 110.
I = 3.5.
R = V/I = 110/3.5 = 31.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers