Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 6)
6.
How much resistance is required to limit the current from a 12 V battery to 3.6 mA?
3.3 k
33 k
2.2 k
22 k
Discussion:
24 comments Page 2 of 3.
Appaso said:
10 years ago
All comments which are given above is totally wrong because ohms law given by them is totally wrong. i is directly proportional to v.
AVATAR said:
1 decade ago
R = V/I.
SO, R = 12/3.6 = 3.333333333333333.
SO, R = 12/3.6 = 3.333333333333333.
PROJIT SAHA said:
1 decade ago
ACCORDING TO OHM'S LAW,
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
R(resistance)=V(voltage)/I(current)
=12/3.6
=3.33 kilo-ohm
Pramod shinva said:
1 decade ago
Over formula is suitable for only in Ohms Volts Amps. So we should be convert mA to Amps.(3.6MA = 3600A).
R = V/I.
= 12/3600.
= 0.0033ohms (0.0033ohms = 3.33 kohms).
= 3.3 kohms.
R = V/I.
= 12/3600.
= 0.0033ohms (0.0033ohms = 3.33 kohms).
= 3.3 kohms.
J.venkatesh said:
1 decade ago
According to ohms law,
V=IR
V=12v
I=3.6ma
R=V/I
I=0.0036AMPS.
R=12/0.036
FINALLY R=3300 OHMS.
R=3.3KOHMS.
V=IR
V=12v
I=3.6ma
R=V/I
I=0.0036AMPS.
R=12/0.036
FINALLY R=3300 OHMS.
R=3.3KOHMS.
Sunny said:
1 decade ago
V=12
I=3.6mA
R=12/3.6*10^-3=12/0.036=3.3kohms.
I=3.6mA
R=12/3.6*10^-3=12/0.036=3.3kohms.
Vikas kumar said:
1 decade ago
V=12, I = 3.6mA=0.0036A.
V=IR.
R=V/I=12/0.0036=12*10^4/36=10^4/3=10000/3=3333.33 ohm.
3.3 kilo ohm.
V=IR.
R=V/I=12/0.0036=12*10^4/36=10^4/3=10000/3=3333.33 ohm.
3.3 kilo ohm.
Tapaswini swain said:
1 decade ago
I=V/R
V=12V
I=3.6mA=3.6*10^-3
R=V/I
R=(12/36*10^-4)Ohm
=(1/3)*10^4ohm
=0.333*10^4ohm
=3.33*10^3ohm
=3.33kilo-ohm
V=12V
I=3.6mA=3.6*10^-3
R=V/I
R=(12/36*10^-4)Ohm
=(1/3)*10^4ohm
=0.333*10^4ohm
=3.33*10^3ohm
=3.33kilo-ohm
Suraj said:
1 decade ago
Absolutely its 3.33kilo ohms.
Anand said:
1 decade ago
Nice answer vinay
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