Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 11)
11.
A resistance of 3.3 M
is connected across a 500 V source. The resulting current is approximately
is connected across a 500 V source. The resulting current is approximatelyDiscussion:
13 comments Page 1 of 2.
KUNAL TANEJA said:
1 decade ago
I=V/R
=500/3.3MOHM
=500/33*10^5
=15.1*10^-5
=151*10^-6
SO ANS IS B
=500/3.3MOHM
=500/33*10^5
=15.1*10^-5
=151*10^-6
SO ANS IS B
Anand said:
1 decade ago
Nice answer Kunal
Ajith said:
10 years ago
I can not understanding. Please give me extra explain.
NAMRATA said:
9 years ago
1Mohm = 10^6.
3.3Mohm = 3.3*10^6.
= 33*10^5.
I = V/R.
= 500/33*10^5.
= 15.1*10^-5.
= 151*10^6.
= 151uA
3.3Mohm = 3.3*10^6.
= 33*10^5.
I = V/R.
= 500/33*10^5.
= 15.1*10^-5.
= 151*10^6.
= 151uA
(2)
Kristian said:
9 years ago
Given: 3.3 Mega ohms= 3,300,000, and 500 volts.
According to ohm's law, I = V/R.
Therefore: I = 500/3,300000.
The answer is B. 151 microampere.
According to ohm's law, I = V/R.
Therefore: I = 500/3,300000.
The answer is B. 151 microampere.
(8)
Pankaj said:
9 years ago
Nice explanation @Kristian.
Shubham said:
9 years ago
1uA = ?
Please tell me.
Please tell me.
Vaibhav said:
9 years ago
10^-6 @Shubham.
Vaibhav said:
9 years ago
10^-6 @Shubham.
Victor said:
8 years ago
Convert the submultiple to multiple 1Amp=10^-6Amp.
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