Electrical Engineering - Ohm's Law - Discussion

Discussion :: Ohm's Law - General Questions (Q.No.11)

11. 

A resistance of 3.3 M is connected across a 500 V source. The resulting current is approximately

[A]. 15.1 µA
[B]. 151 µA
[C]. 66 mA
[D]. 660 mA

Answer: Option B

Explanation:

No answer description available for this question.

Kunal Taneja said: (Feb 10, 2011)  
I=V/R
=500/3.3MOHM
=500/33*10^5
=15.1*10^-5
=151*10^-6
SO ANS IS B

Anand said: (Jul 22, 2011)  
Nice answer Kunal

Ajith said: (Sep 22, 2015)  
I can not understanding. Please give me extra explain.

Namrata said: (Mar 18, 2016)  
1Mohm = 10^6.
3.3Mohm = 3.3*10^6.
= 33*10^5.

I = V/R.
= 500/33*10^5.
= 15.1*10^-5.
= 151*10^6.
= 151uA

Kristian said: (May 3, 2016)  
Given: 3.3 Mega ohms= 3,300,000, and 500 volts.

According to ohm's law, I = V/R.

Therefore: I = 500/3,300000.

The answer is B. 151 microampere.

Pankaj said: (Sep 17, 2016)  
Nice explanation @Kristian.

Shubham said: (Nov 22, 2016)  
1uA = ?

Please tell me.

Vaibhav said: (Jan 19, 2017)  
10^-6 @Shubham.

Vaibhav said: (Jan 19, 2017)  
10^-6 @Shubham.

Victor said: (Sep 30, 2017)  
Convert the submultiple to multiple 1Amp=10^-6Amp.

Javed Jamshed said: (Oct 18, 2018)  
Helpful explanation. Thanks all.

Barkat Kanhar said: (Feb 22, 2020)  
Very helpful thank you, friends.

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