Electrical Engineering - Ohm's Law - Discussion

Discussion :: Ohm's Law - General Questions (Q.No.11)

11.

A resistance of 3.3 M is connected across a 500 V source. The resulting current is approximately

 [A]. 15.1 µA [B]. 151 µA [C]. 66 mA [D]. 660 mA

Explanation:

No answer description available for this question.

 Kunal Taneja said: (Feb 10, 2011) I=V/R =500/3.3MOHM =500/33*10^5 =15.1*10^-5 =151*10^-6 SO ANS IS B

 Anand said: (Jul 22, 2011) Nice answer Kunal

 Ajith said: (Sep 22, 2015) I can not understanding. Please give me extra explain.

 Namrata said: (Mar 18, 2016) 1Mohm = 10^6. 3.3Mohm = 3.3*10^6. = 33*10^5. I = V/R. = 500/33*10^5. = 15.1*10^-5. = 151*10^6. = 151uA

 Kristian said: (May 3, 2016) Given: 3.3 Mega ohms= 3,300,000, and 500 volts. According to ohm's law, I = V/R. Therefore: I = 500/3,300000. The answer is B. 151 microampere.

 Pankaj said: (Sep 17, 2016) Nice explanation @Kristian.

 Shubham said: (Nov 22, 2016) 1uA = ? Please tell me.

 Vaibhav said: (Jan 19, 2017) 10^-6 @Shubham.

 Vaibhav said: (Jan 19, 2017) 10^-6 @Shubham.

 Victor said: (Sep 30, 2017) Convert the submultiple to multiple 1Amp=10^-6Amp.

 Javed Jamshed said: (Oct 18, 2018) Helpful explanation. Thanks all.

 Barkat Kanhar said: (Feb 22, 2020) Very helpful thank you, friends.