Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 10)
10.
When there is 12 mA of current through a 1.2 k resistor, the voltage across the resistor is
14.4 V
1.4 V
100 V
10 V
Answer: Option
Explanation:

V = IR (Ohms Law)

= 12 X 10-3 X 1.2 X 10 3

= 12 X 1.2

= 14.4 V

Discussion:
8 comments Page 1 of 1.

Johnlerr Espenoza said:   2 years ago
V = I × R.
V = 12 × 1200.
= 14.4V.

Robert Kula said:   3 years ago
V = IR.
I = 12MA,
R = 1.2KILO OHMS,
1A = 1000MA.

What about 12ma,
1a * 12ma/1000ma,
= 0.012a.

1kilohms = 1000 ohms,
what about 1.2kilohms.
1000 ohm * 1.2kiloohms/1kiloohms = 0.0012 ohms.
= 1200.
1200 * 0.012 = 14.4v.

Srinivasulu said:   8 years ago
Arun it's milli ampere not mega ampere, 1.2*12 = 14.4v.

AVATAR said:   1 decade ago
V = IR.

SO, V = 12/1000*1.2*1000 = 14.4V.

Pandurang said:   1 decade ago
12mA = 1.2 X 10^-2 A.
1.2 Kohm = 1.2 X 10^3 ohm.

V = I X R.
= 1.2X10^-2 X 1.2x10^3.
= 14.4.

Vishal said:   1 decade ago
@Arun i think you are wrong...

See clearly he changed value 12 ma to 1.2 *10^-2.

Hope so you understand:)

Arun said:   1 decade ago
Jay deep is wrong.

Here.

For mA=mega Ampere sp its belongs to 10^-3 A.

Jaydeep said:   1 decade ago
12mA = 1.2 X 10^-2 A
1.2 Kohm = 1.2 X 10^3 oham


V = I X R
=1.2X10^-2 X 1.2x10^3
= 14.4

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