Electrical Engineering - Ohm's Law - Discussion

Discussion :: Ohm's Law - General Questions (Q.No.10)

10. 

When there is 12 mA of current through a 1.2 k resistor, the voltage across the resistor is

[A]. 14.4 V
[B]. 1.4 V
[C]. 100 V
[D]. 10 V

Answer: Option A

Explanation:

V = IR (Ohms Law)

= 12 X 10-3 X 1.2 X 10 3

= 12 X 1.2

= 14.4 V


Jaydeep said: (Jun 18, 2011)  
12mA = 1.2 X 10^-2 A
1.2 Kohm = 1.2 X 10^3 oham


V = I X R
=1.2X10^-2 X 1.2x10^3
= 14.4

Arun said: (Aug 3, 2011)  
Jay deep is wrong.

Here.

For mA=mega Ampere sp its belongs to 10^-3 A.

Vishal said: (Jan 24, 2012)  
@Arun i think you are wrong...

See clearly he changed value 12 ma to 1.2 *10^-2.

Hope so you understand:)

Pandurang said: (Aug 14, 2013)  
12mA = 1.2 X 10^-2 A.
1.2 Kohm = 1.2 X 10^3 ohm.

V = I X R.
= 1.2X10^-2 X 1.2x10^3.
= 14.4.

Avatar said: (Oct 8, 2014)  
V = IR.

SO, V = 12/1000*1.2*1000 = 14.4V.

Srinivasulu said: (Sep 26, 2017)  
Arun it's milli ampere not mega ampere, 1.2*12 = 14.4v.

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