Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 3)
3.
For a given wirewound core, an increase in current through the coil
Discussion:
8 comments Page 1 of 1.
Praveen said:
1 decade ago
As current increases means flux increases by formula pi=n*i.
Sunitha said:
1 decade ago
As we know that Flux density B = Q/N.
Q - Flux.
N - No. on turns.
As current increases, flux increases then obviously flux density increases because flux is directly proportional to flux density.
Q - Flux.
N - No. on turns.
As current increases, flux increases then obviously flux density increases because flux is directly proportional to flux density.
Brahma krishna said:
1 decade ago
Because high voltage induced flux is more.
ROSHIK said:
1 decade ago
When the current flowing through more large the flux is also increased and it increase. The flux density.
Venkatesh said:
10 years ago
We know:
1) pi = NI/S.
2) B = pi/A.
From above relations we can say that as I increases pi increases therefore B of coil increases respectively.
1) pi = NI/S.
2) B = pi/A.
From above relations we can say that as I increases pi increases therefore B of coil increases respectively.
Stark said:
9 years ago
Here the current passing through the conductor is directly proportional to flux density.
(1)
Parimal bera said:
8 years ago
We know that the current directly proportional to flux density (B).
(1)
Amardeep said:
5 years ago
We know flux density is directly proportional to current.
When current is high flux density is high.
When current is high flux density is high.
(2)
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