Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 3)
3.
For a given wirewound core, an increase in current through the coil
Discussion:
8 comments Page 1 of 1.
Amardeep said:
5 years ago
We know flux density is directly proportional to current.
When current is high flux density is high.
When current is high flux density is high.
(2)
Parimal bera said:
8 years ago
We know that the current directly proportional to flux density (B).
(1)
Stark said:
9 years ago
Here the current passing through the conductor is directly proportional to flux density.
(1)
Venkatesh said:
10 years ago
We know:
1) pi = NI/S.
2) B = pi/A.
From above relations we can say that as I increases pi increases therefore B of coil increases respectively.
1) pi = NI/S.
2) B = pi/A.
From above relations we can say that as I increases pi increases therefore B of coil increases respectively.
ROSHIK said:
1 decade ago
When the current flowing through more large the flux is also increased and it increase. The flux density.
Brahma krishna said:
1 decade ago
Because high voltage induced flux is more.
Sunitha said:
1 decade ago
As we know that Flux density B = Q/N.
Q - Flux.
N - No. on turns.
As current increases, flux increases then obviously flux density increases because flux is directly proportional to flux density.
Q - Flux.
N - No. on turns.
As current increases, flux increases then obviously flux density increases because flux is directly proportional to flux density.
Praveen said:
1 decade ago
As current increases means flux increases by formula pi=n*i.
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